What is the perpendicular y= 2/3 x+c ?

The perpendicular y= 2/3 x+c is y=-3/2 x+b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

perpendicular y= 2/3 x+c

perpendicular

y = \frac{2}{3} x + c

y = - \frac{3}{2} x + b

Solution steps

Find the slope of

y = \frac{2}{3} x + c : m = \frac{2}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{2}

Line with slope m=

- \frac{3}{2} : y = - \frac{3}{2} x + b

y = - \frac{3}{2} x + b

What is the perpendicular y= 2/3 x+c ?
The perpendicular y= 2/3 x+c is y=-3/2 x+b