What is the extreme f(x)=2x^3+3x^2-72x ?

The extreme f(x)=2x^3+3x^2-72x is Maximum(-4,208),Minimum(3,-135)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=2x^3+3x^2-72x

extreme points

f (x) = 2 x^{3} + 3 x^{2} - 72 x

Maximum (- 4, 208), Minimum (3, - 135)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 72

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 4

into

2 x^{3} + 3 x^{2} - 72 x : 208

Maximum (- 4, 208)

Plug

x = 3

into

2 x^{3} + 3 x^{2} - 72 x : - 135

Minimum (3, - 135)

Maximum (- 4, 208), Minimum (3, - 135)

What is the extreme f(x)=2x^3+3x^2-72x ?
The extreme f(x)=2x^3+3x^2-72x is Maximum(-4,208),Minimum(3,-135)