What is the inverse of f(x)=(x-3)^2+1/2 ?

The inverse of f(x)=(x-3)^2+1/2 is sqrt((2x-1)/2)+3,-sqrt((2x-1)/2)+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=(x-3)^2+1/2

inverse

f (x) = (x - 3)^{2} + \frac{1}{2}

\frac{2 x - 1}{2} + 3, - \frac{2 x - 1}{2} + 3

Solution steps

y = (x - 3)^{2} + \frac{1}{2}

Replace

x

with

y

x = (y - 3)^{2} + \frac{1}{2}

Solve for

y, x = (y - 3)^{2} + \frac{1}{2}

\frac{2 x - 1}{2} + 3, - \frac{2 x - 1}{2} + 3

What is the inverse of f(x)=(x-3)^2+1/2 ?
The inverse of f(x)=(x-3)^2+1/2 is sqrt((2x-1)/2)+3,-sqrt((2x-1)/2)+3