What is the inverse of f(x)= 1/4 (x+3)^2-5 ?

The inverse of f(x)= 1/4 (x+3)^2-5 is 2sqrt(x+5)-3,-2sqrt(x+5)-3

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inverse of f(x)= 1/4 (x+3)^2-5

inverse

f (x) = \frac{1}{4} (x + 3)^{2} - 5

2 x + 5 - 3, - 2 x + 5 - 3

Solution steps

y = \frac{1}{4} (x + 3)^{2} - 5

Replace

x

with

y

x = \frac{1}{4} (y + 3)^{2} - 5

Solve for

y, x = \frac{1}{4} (y + 3)^{2} - 5

2 x + 5 - 3, - 2 x + 5 - 3

What is the inverse of f(x)= 1/4 (x+3)^2-5 ?
The inverse of f(x)= 1/4 (x+3)^2-5 is 2sqrt(x+5)-3,-2sqrt(x+5)-3