What is the extreme f(x)=x^3-6x^2-135x ?

The extreme f(x)=x^3-6x^2-135x is Maximum(-5,400),Minimum(9,-972)

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extreme f(x)=x^3-6x^2-135x

extreme points

f (x) = x^{3} - 6 x^{2} - 135 x

Maximum (- 5, 400), Minimum (9, - 972)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x - 135

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = - 5

into

x^{3} - 6 x^{2} - 135 x : 400

Maximum (- 5, 400)

Plug

x = 9

into

x^{3} - 6 x^{2} - 135 x : - 972

Minimum (9, - 972)

Maximum (- 5, 400), Minimum (9, - 972)

What is the extreme f(x)=x^3-6x^2-135x ?
The extreme f(x)=x^3-6x^2-135x is Maximum(-5,400),Minimum(9,-972)