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midpoint
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range of f(x)=((4x^2-1))/(|2x+1|)domain of sqrt(x^2+16)range of f(x)= 5/(sqrt(x-9))inverse of f(x)=arcsec(x)domain of f(x)=9-(x-2)^2
Frequently Asked Questions (FAQ)
What is the midpoint (8,1),(-2,-5) ?
The midpoint (8,1),(-2,-5) is (3,-2)