What is the inverse of f(x)=4(x+3)^2-8 ?

The inverse of f(x)=4(x+3)^2-8 is (sqrt(x+8))/2-3,-(sqrt(x+8))/2-3

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inverse of f(x)=4(x+3)^2-8

inverse

f (x) = 4 (x + 3)^{2} - 8

\frac{x + 8}{2} - 3, - \frac{x + 8}{2} - 3

Solution steps

y = 4 (x + 3)^{2} - 8

Replace

x

with

y

x = 4 (y + 3)^{2} - 8

Solve for

y, x = 4 (y + 3)^{2} - 8

\frac{x + 8}{2} - 3, - \frac{x + 8}{2} - 3

What is the inverse of f(x)=4(x+3)^2-8 ?
The inverse of f(x)=4(x+3)^2-8 is (sqrt(x+8))/2-3,-(sqrt(x+8))/2-3