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midpoint
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parity x^{3/5}cos(tan(ax)+e^{6x})asymptotes of f(x)=(x^3-1)/(x^2-1)extreme f(x)=3x^2+3inverse of y=(2x^2-1)/4inverse of y=ln(4x-10)-6
Frequently Asked Questions (FAQ)
What is the midpoint (5,7),(-5,-4) ?
The midpoint (5,7),(-5,-4) is (0, 3/2)