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parity f(x)=(4x^2-5)/(2x^3+x)perpendicular 4x+3y=9distance (1,1),(3,4)critical f(x)=x^4-2x^2+2amplitude of-cos(x)

Frequently Asked Questions (FAQ)

  • What is the inverse of f(x)=x^{1/3}-9 ?

    The inverse of f(x)=x^{1/3}-9 is x^3+27x^2+243x+729