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midpoint
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domain of (x-3)/(2x^2)inverse of f(x)=((x+4))/(x-2)shift f(x)=-3sin(x-pi/4)+2symmetry y=2(x-4)^2+3domain of f(x)=(5x+20)/(x^2-16)
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-6),(2,-11) ?
The midpoint (-2,-6),(2,-11) is (0,-17/2)