What is the range of 4/7 sin(-(2pi)/7 x) ?

The range of 4/7 sin(-(2pi)/7 x) is -4/7 <= f(x)<= 4/7

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range of 4/7 sin(-(2pi)/7 x)

range

\frac{4}{7} sin (- \frac{2 π}{7} x)

- \frac{4}{7} \leq f (x) \leq \frac{4}{7}

Interval Notation

[- \frac{4}{7}, \frac{4}{7}]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (- \frac{2 π}{7} x) \leq 1

- 1 \leq sin (- \frac{2 π}{7} x) \leq 1

Multiply the edges of the range by:

\frac{4}{7}

- \frac{4}{7} \leq \frac{4}{7} sin (- \frac{2 π}{7} x) \leq \frac{4}{7}

Therefore the range is

- \frac{4}{7} \leq f (x) \leq \frac{4}{7}

What is the range of 4/7 sin(-(2pi)/7 x) ?
The range of 4/7 sin(-(2pi)/7 x) is -4/7 <= f(x)<= 4/7