What is the inverse of f(x)=2(x-1)^2-5 ?

The inverse of f(x)=2(x-1)^2-5 is sqrt((x+5)/2)+1,-sqrt((x+5)/2)+1

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inverse of f(x)=2(x-1)^2-5

inverse

f (x) = 2 (x - 1)^{2} - 5

\frac{x + 5}{2} + 1, - \frac{x + 5}{2} + 1

Solution steps

y = 2 (x - 1)^{2} - 5

Replace

x

with

y

x = 2 (y - 1)^{2} - 5

Solve for

y, x = 2 (y - 1)^{2} - 5

\frac{x + 5}{2} + 1, - \frac{x + 5}{2} + 1

What is the inverse of f(x)=2(x-1)^2-5 ?
The inverse of f(x)=2(x-1)^2-5 is sqrt((x+5)/2)+1,-sqrt((x+5)/2)+1