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midpoint
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asymptotes of f(x)=(x^2-2x)/(2x^2+2x-12)range of (-5)/(sqrt(1-x))range of f(x)= 3/(x^2)inverse of 2x^2(sqrt(2)+1)slope of x= 3/5
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-7),(2.5,-1.5) ?
The midpoint (-2,-7),(2.5,-1.5) is (0.25,-4.25)