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inverse of f(x)=7+1/5 xmidpoint (-5/2 , 1/2),(-7/2 ,-9/2)domain of f(x)=(2x^2-x-1)/(x^2+9)inverse of f(x)=(16-t)^{1/8}range of-2/(sqrt(x))
Frequently Asked Questions (FAQ)
What is the symmetry y=3-x^2 ?
The symmetry y=3-x^2 is x=0