What is the extreme f(x)=x^3-27x+4 ?

The extreme f(x)=x^3-27x+4 is Maximum(-3,58),Minimum(3,-50)

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extreme f(x)=x^3-27x+4

extreme points

f (x) = x^{3} - 27 x + 4

Maximum (- 3, 58), Minimum (3, - 50)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 4 : 58

Maximum (- 3, 58)

Plug

x = 3

into

x^{3} - 27 x + 4 : - 50

Minimum (3, - 50)

Maximum (- 3, 58), Minimum (3, - 50)

What is the extreme f(x)=x^3-27x+4 ?
The extreme f(x)=x^3-27x+4 is Maximum(-3,58),Minimum(3,-50)