What is the extreme f(x)=sqrt(25-x^2) ?

The extreme f(x)=sqrt(25-x^2) is Minimum(-5,0),Maximum(0,5),Minimum(5,0)

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extreme f(x)=sqrt(25-x^2)

extreme points

f (x) = 25 - x^{2}

Minimum (- 5, 0), Maximum (0, 5), Minimum (5, 0)

Solution steps

f^{'} (x) = - \frac{x}{25 - x ^{2}}

Find intervals:

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5

Plug

x = - 5

into

25 - x^{2} : 0

Minimum (- 5, 0)

Plug

x = 0

into

25 - x^{2} : 5

Maximum (0, 5)

Plug

x = 5

into

25 - x^{2} : 0

Minimum (5, 0)

Minimum (- 5, 0), Maximum (0, 5), Minimum (5, 0)

What is the extreme f(x)=sqrt(25-x^2) ?
The extreme f(x)=sqrt(25-x^2) is Minimum(-5,0),Maximum(0,5),Minimum(5,0)