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Popular Functions >

extreme f(x)=x^2+7x+8

Solution

extreme points

f (x) = x^{2} + 7 x + 8

Solution

Minimum (- \frac{7}{2}, - \frac{17}{4})

Solution steps

f^{'} (x) = 2 x + 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{2},

Increasing

: - \frac{7}{2} < x < \infty

Plug

x = - \frac{7}{2}

into

x^{2} + 7 x + 8 : - \frac{17}{4}

Minimum (- \frac{7}{2}, - \frac{17}{4})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+7x+8 ?
The extreme f(x)=x^2+7x+8 is Minimum(-7/2 ,-17/4)