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Popular Functions >

extreme f(x)= 8/(x^2+4)

Solution

extreme points

f (x) = \frac{8}{x ^{2} + 4}

Solution

Maximum (0, 2)

Solution steps

f^{'} (x) = - \frac{16 x}{( x ^{2} + 4 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{8}{x ^{2} + 4} : 2

Maximum (0, 2)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)= 8/(x^2+4) ?
The extreme f(x)= 8/(x^2+4) is Maximum(0,2)