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Popular Functions >

midpoint (12,2),(8,-4)

Solution

midpoint

(12, 2), (8, - 4)

Solution

(10, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (12, 2), (x_{2}, y_{2}) = (8, - 4)

= (\frac{8 + 12}{2}, \frac{- 4 + 2}{2})

Refine

= (10, - 1)

Graph

Popular Examples

critical (-x^3)/4+2x^2+8/3-4x

monotone f(x)=x^2-5x

range of-sqrt(2x-3)+6

domain of x^3+2x^2-3x+1

Frequently Asked Questions (FAQ)

What is the midpoint (12,2),(8,-4) ?
The midpoint (12,2),(8,-4) is (10,-1)