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Popular Functions >

extreme f(x)=ln(2-x^2)

Solution

extreme points

f (x) = ln (2 - x^{2})

Solution

Maximum (0, ln (2))

Solution steps

f^{'} (x) = - \frac{2 x}{2 - x ^{2}}

Find intervals:

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2

Plug

x = 0

into

ln (2 - x^{2}) : ln (2)

Maximum (0, ln (2))

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(2-x^2) ?
The extreme f(x)=ln(2-x^2) is Maximum(0,ln(2))