What is the monotone f(x)= 1/(6x^2+1) ?

The monotone f(x)= 1/(6x^2+1) is Increasing:-infinity <x<0,Decreasing:0<x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

monotone f(x)= 1/(6x^2+1)

monotone intervals

f (x) = \frac{1}{6 x ^{2} + 1}

Increasing : - \infty < x < 0, Decreasing : 0 < x < \infty

Solution steps

f^{'} (x) = - \frac{12 x}{( 6 x ^{2} + 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Increasing : - \infty < x < 0, Decreasing : 0 < x < \infty

What is the monotone f(x)= 1/(6x^2+1) ?
The monotone f(x)= 1/(6x^2+1) is Increasing:-infinity <x<0,Decreasing:0<x<infinity