What is the domain of y=(sqrt(x+8))/(x-7) ?

The domain of y=(sqrt(x+8))/(x-7) is -8 7

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domain of y=(sqrt(x+8))/(x-7)

domain

y = \frac{x + 8}{x - 7}

- 8 \leq x < 7 or x > 7

Interval Notation

[- 8, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

- 8 \leq x < 7 or x > 7

What is the domain of y=(sqrt(x+8))/(x-7) ?
The domain of y=(sqrt(x+8))/(x-7) is -8<= x<7\lor x>7