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midpoint
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domain of f(x)=(sqrt(x-5))/(x-11)inverse of f(x)=1-1/5 xparity f(x)=(3x^5)/(2x^3+x)domain of-1/(2x^{3/2)}critical f(x)=-4x^2+48x
Frequently Asked Questions (FAQ)
What is the midpoint (1,-7),(-4,1) ?
The midpoint (1,-7),(-4,1) is (-3/2 ,-3)