What is the domain of f(x)=(sqrt(2x-8))/(x^2-9) ?

The domain of f(x)=(sqrt(2x-8))/(x^2-9) is x>= 4

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domain of f(x)=(sqrt(2x-8))/(x^2-9)

domain

f (x) = \frac{2 x - 8}{x ^{2} - 9}

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x \geq 4

What is the domain of f(x)=(sqrt(2x-8))/(x^2-9) ?
The domain of f(x)=(sqrt(2x-8))/(x^2-9) is x>= 4