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midpoint
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inverse of 3x+10asymptotes of f(x)=(2x^2)/(x^2-8x+16)asymptotes of f(x)=(x^2-3x-5)/(x+2)inverse of 1/(s+2)extreme f(x)=x^4-7x^2+8
Frequently Asked Questions (FAQ)
What is the midpoint (3,6),(-4,-1) ?
The midpoint (3,6),(-4,-1) is (-1/2 , 5/2)