What is the domain of f(x)= 6/(sqrt(16-x^2)) ?

The domain of f(x)= 6/(sqrt(16-x^2)) is -4<x<4

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domain of f(x)= 6/(sqrt(16-x^2))

domain

f (x) = \frac{6}{16 - x ^{2}}

- 4 < x < 4

Interval Notation

(- 4, 4)

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq 4

Find undefined (singularity) points:

x = 4, x = - 4

Combine real regions and undefined points for final function domain

- 4 < x < 4

What is the domain of f(x)= 6/(sqrt(16-x^2)) ?
The domain of f(x)= 6/(sqrt(16-x^2)) is -4<x<4