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midpoint

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inverse of f(x)=x^3-5domain of f(x)=((2x^3-5))/(x^2+x-6)extreme f(x)= x/(x^2+1)inverse of y=f(x)=(2-5x)/(6-6x)range of f(x)=6x

Frequently Asked Questions (FAQ)

  • What is the midpoint (7,-2),(-5,-2) ?

    The midpoint (7,-2),(-5,-2) is (1,-2)