What is the extreme f(x)=x^3-9x^2-120x+6 ?

The extreme f(x)=x^3-9x^2-120x+6 is Maximum(-4,278),Minimum(10,-1094)

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extreme f(x)=x^3-9x^2-120x+6

extreme points

f (x) = x^{3} - 9 x^{2} - 120 x + 6

Maximum (- 4, 278), Minimum (10, - 1094)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x - 120

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 10,

Increasing

: 10 < x < \infty

Plug

x = - 4

into

x^{3} - 9 x^{2} - 120 x + 6 : 278

Maximum (- 4, 278)

Plug

x = 10

into

x^{3} - 9 x^{2} - 120 x + 6 : - 1094

Minimum (10, - 1094)

Maximum (- 4, 278), Minimum (10, - 1094)

What is the extreme f(x)=x^3-9x^2-120x+6 ?
The extreme f(x)=x^3-9x^2-120x+6 is Maximum(-4,278),Minimum(10,-1094)