What is the shift f(x)=5sin(4x+2pi) ?

The shift f(x)=5sin(4x+2pi) is Phase:-pi/2 , Vertical:0

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shift f(x)=5sin(4x+2pi)

shift

f (x) = 5 sin (4 x + 2 π)

Phase : - \frac{π}{2}, Vertical : 0

Solution steps

f (x) = 5 sin (4 x + 2 π)

g (B x - C) = sin (4 x + 2 π), B = 4, C = - 2 π, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- 2 π}{4}

- \frac{π}{2}

The vertical shift

D

0

0

What is the shift f(x)=5sin(4x+2pi) ?
The shift f(x)=5sin(4x+2pi) is Phase:-pi/2 , Vertical:0