What is the inverse of f(x)=4(x-1)^2-3 ?

The inverse of f(x)=4(x-1)^2-3 is (sqrt(x+3))/2+1,-(sqrt(x+3))/2+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=4(x-1)^2-3

inverse

f (x) = 4 (x - 1)^{2} - 3

\frac{x + 3}{2} + 1, - \frac{x + 3}{2} + 1

Solution steps

y = 4 (x - 1)^{2} - 3

Replace

x

with

y

x = 4 (y - 1)^{2} - 3

Solve for

y, x = 4 (y - 1)^{2} - 3

\frac{x + 3}{2} + 1, - \frac{x + 3}{2} + 1

What is the inverse of f(x)=4(x-1)^2-3 ?
The inverse of f(x)=4(x-1)^2-3 is (sqrt(x+3))/2+1,-(sqrt(x+3))/2+1