What is the inverse of f(x)=5(3x-1)^2+25 ?

The inverse of f(x)=5(3x-1)^2+25 is (sqrt((x-25)/5)+1)/(3),(-sqrt((x-25)/5)+1)/(3)

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inverse of f(x)=5(3x-1)^2+25

inverse

f (x) = 5 (3 x - 1)^{2} + 25

\frac{\frac{x - 25}{5} + 1}{3}, \frac{- \frac{x - 25}{5} + 1}{3}

Solution steps

y = 5 (3 x - 1)^{2} + 25

Replace

x

with

y

x = 5 (3 y - 1)^{2} + 25

Solve for

y, x = 5 (3 y - 1)^{2} + 25

\frac{\frac{x - 25}{5} + 1}{3}, \frac{- \frac{x - 25}{5} + 1}{3}

What is the inverse of f(x)=5(3x-1)^2+25 ?
The inverse of f(x)=5(3x-1)^2+25 is (sqrt((x-25)/5)+1)/(3),(-sqrt((x-25)/5)+1)/(3)