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Popular Functions >

extreme f(x)=-2/(x^2-16)

Solution

extreme points

f (x) = - \frac{2}{x ^{2} - 16}

Solution

Minimum (0, \frac{1}{8})

Solution steps

f^{'} (x) = \frac{4 x}{( x ^{2} - 16 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Increasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

- \frac{2}{x ^{2} - 16} : \frac{1}{8}

Minimum (0, \frac{1}{8})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2/(x^2-16) ?
The extreme f(x)=-2/(x^2-16) is Minimum(0, 1/8)