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Popular Functions >

inverse of f(x)=(2x^4+7)/(1+x^2)

Solution

inverse

f (x) = \frac{2 x ^{4} + 7}{1 + x ^{2}}

Solution

\frac{x + x ^{2} - 8 ( 7 - x )}{2}, - \frac{x + x ^{2} - 8 ( 7 - x )}{2}, \frac{x - x ^{2} - 8 ( 7 - x )}{2}, - \frac{x - x ^{2} - 8 ( 7 - x )}{2}

Solution steps

y = \frac{2 x ^{4} + 7}{1 + x ^{2}}

Replace

x

with

y

x = \frac{2 y ^{4} + 7}{1 + y ^{2}}

Solve for

y, x = \frac{2 y ^{4} + 7}{1 + y ^{2}}

\frac{x + x ^{2} - 8 ( 7 - x )}{2}, - \frac{x + x ^{2} - 8 ( 7 - x )}{2}, \frac{x - x ^{2} - 8 ( 7 - x )}{2}, - \frac{x - x ^{2} - 8 ( 7 - x )}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the inverse of f(x)=(2x^4+7)/(1+x^2) ?
The inverse of f(x)=(2x^4+7)/(1+x^2) is