What is the inverse of f(x)= 3/(x^2+2x) ?

The inverse of f(x)= 3/(x^2+2x) is (-x+sqrt(x(x+3)))/x ,-(x+sqrt(x(x+3)))/x

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inverse of f(x)= 3/(x^2+2x)

inverse

f (x) = \frac{3}{x ^{2} + 2 x}

\frac{- x + x ( x + 3 )}{x}, - \frac{x + x ( x + 3 )}{x}

Solution steps

y = \frac{3}{x ^{2} + 2 x}

Replace

x

with

y

x = \frac{3}{y ^{2} + 2 y}

Solve for

y, x = \frac{3}{y ^{2} + 2 y}

\frac{- x + x ( x + 3 )}{x}, - \frac{x + x ( x + 3 )}{x}

What is the inverse of f(x)= 3/(x^2+2x) ?
The inverse of f(x)= 3/(x^2+2x) is (-x+sqrt(x(x+3)))/x ,-(x+sqrt(x(x+3)))/x