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Popular Functions >

range of (x^2+12)/3

Solution

range

\frac{x ^{2} + 12}{3}

Solution

f (x) \geq 4

+1

Interval Notation

[4, \infty)

Solution steps

Vertex of

\frac{x ^{2} + 12}{3} :

Minimum

(0, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = \frac{1}{3},

Vertex

(x_{v}, y_{v}) = (0, 4)

f (x) \geq 4

Graph

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Frequently Asked Questions (FAQ)

What is the range of (x^2+12)/3 ?
The range of (x^2+12)/3 is f(x)>= 4