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midpoint
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parity f(x)=sin(x)cos(x)domain of (2-x^2)/(x^2-9)domain of f(x)=(2x-1)/(4+5x)inverse of sqrt(x-2)intercepts of f(x)=x^2+x+2/(x-1)
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-4),(2,-10) ?
The midpoint (-2,-4),(2,-10) is (0,-7)