What is the domain of f(x)=(sqrt(4-x^2))/(x^2+6x-7) ?

The domain of f(x)=(sqrt(4-x^2))/(x^2+6x-7) is -2<= x<1\lor 1<x<= 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)=(sqrt(4-x^2))/(x^2+6x-7)

domain

f (x) = \frac{4 - x ^{2}}{x ^{2} + 6 x - 7}

- 2 \leq x < 1 or 1 < x \leq 2

Interval Notation

[- 2, 1) \cup (1, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

Find undefined (singularity) points:

x = 1, x = - 7

Combine real regions and undefined points for final function domain

- 2 \leq x < 1 or 1 < x \leq 2

What is the domain of f(x)=(sqrt(4-x^2))/(x^2+6x-7) ?
The domain of f(x)=(sqrt(4-x^2))/(x^2+6x-7) is -2<= x<1\lor 1<x<= 2