What is the inverse of f(x)=(x-2)(x+1) ?

The inverse of f(x)=(x-2)(x+1) is (1+sqrt(4x+9))/2 ,(1-sqrt(4x+9))/2

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inverse of f(x)=(x-2)(x+1)

inverse

f (x) = (x - 2) (x + 1)

\frac{1 + 4 x + 9}{2}, \frac{1 - 4 x + 9}{2}

Solution steps

y = (x - 2) (x + 1)

Replace

x

with

y

x = (y - 2) (y + 1)

Solve for

y, x = (y - 2) (y + 1)

\frac{1 + 4 x + 9}{2}, \frac{1 - 4 x + 9}{2}

What is the inverse of f(x)=(x-2)(x+1) ?
The inverse of f(x)=(x-2)(x+1) is (1+sqrt(4x+9))/2 ,(1-sqrt(4x+9))/2