What is the perpendicular-4x+y=19,(-4,2) ?

The perpendicular-4x+y=19,(-4,2) is y=-1/4 x+1

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perpendicular-4x+y=19,(-4,2)

perpendicular

- 4 x + y = 19, (- 4, 2)

y = - \frac{1}{4} x + 1

Solution steps

Find the line

y = mx + b

perpendicular to

- 4 x + y = 19

that passes through

(- 4, 2)

Find the slope of

- 4 x + y = 19 : m = 4

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(- 4, 2) : y = - \frac{1}{4} x + 1

y = - \frac{1}{4} x + 1

What is the perpendicular-4x+y=19,(-4,2) ?
The perpendicular-4x+y=19,(-4,2) is y=-1/4 x+1