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midpoint
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domain of (sqrt(25-x^2))/(sqrt(x+1))asymptotes of f(x)= 2/(x-4)slope ofintercept 5x-y=2inflection (8x)/(x^2+1)inverse of f(x)= 1/(x+2)
Frequently Asked Questions (FAQ)
What is the midpoint (-1,1),(-6,-3) ?
The midpoint (-1,1),(-6,-3) is (-7/2 ,-1)