What is the y=-(x^2)/(10)+(9x)/(10)+11/5 ?

The y=-(x^2)/(10)+(9x)/(10)+11/5 is

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y=-(x^2)/(10)+(9x)/(10)+11/5

y = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

Domain : - \infty < x < \infty

Range : f (x) \leq \frac{169}{40}

X Intercepts : (- 2, 0), (11, 0), Y Intercepts : (0, \frac{11}{5})

Vertex : Maximum (\frac{9}{2}, \frac{169}{40})

Inverse : - \frac{- 9 + - 40 x + 169}{2}, - \frac{- 9 - - 40 x + 169}{2}

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \frac{169}{40}]

Solution steps

Domain of

- \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5} : - \infty < x < \infty

Range of

- \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5} : f (x) \leq \frac{169}{40}

Axis interception points of

- \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5} :

X Intercepts

: (- 2, 0), (11, 0),

Y Intercepts

: (0, \frac{11}{5})

Vertex of

- \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5} :

Maximum

(\frac{9}{2}, \frac{169}{40})

Inverse of

- \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5} : - \frac{- 9 + - 40 x + 169}{2}, - \frac{- 9 - - 40 x + 169}{2}