What is the perpendicular y= 2/3 x+1,(3,-1) ?

The perpendicular y= 2/3 x+1,(3,-1) is y=-3/2 x+7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

perpendicular y= 2/3 x+1,(3,-1)

perpendicular

y = \frac{2}{3} x + 1, (3, - 1)

y = - \frac{3}{2} x + \frac{7}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{2}{3} x + 1

that passes through

(3, - 1)

Find the slope of

y = \frac{2}{3} x + 1 : m = \frac{2}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(3, - 1) : y = - \frac{3}{2} x + \frac{7}{2}

y = - \frac{3}{2} x + \frac{7}{2}

What is the perpendicular y= 2/3 x+1,(3,-1) ?
The perpendicular y= 2/3 x+1,(3,-1) is y=-3/2 x+7/2