What is the range of 2/(x^2)+9 ?

The range of 2/(x^2)+9 is f(x)>9

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range of 2/(x^2)+9

range

\frac{2}{x ^{2}} + 9

f (x) > 9

Interval Notation

(9, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{2}{x ^{2}} + 9

Inverse of

\frac{2}{x ^{2}} + 9 : \frac{2}{x - 9}, - \frac{2}{x - 9}

\frac{2}{x - 9}, - \frac{2}{x - 9}

Find the domain of each inverse function

Domain of

\frac{2}{x - 9} : x > 9

Domain of

- \frac{2}{x - 9} : x > 9

Combine the intervals

f (x) > 9