What is the inverse of (x^2-4)/(8x^2) ?

The inverse of (x^2-4)/(8x^2) is sqrt(-4/(8x-1)),-sqrt(-4/(8x-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of (x^2-4)/(8x^2)

inverse

\frac{x ^{2} - 4}{8 x ^{2}}

- \frac{4}{8 x - 1}, - - \frac{4}{8 x - 1}

Solution steps

y = \frac{x ^{2} - 4}{8 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 4}{8 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 4}{8 y ^{2}}

- \frac{4}{8 x - 1}, - - \frac{4}{8 x - 1}

What is the inverse of (x^2-4)/(8x^2) ?
The inverse of (x^2-4)/(8x^2) is sqrt(-4/(8x-1)),-sqrt(-4/(8x-1))