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Popular Functions >

extreme y=x^3+12x^2+48x-1

Solution

extreme points

y = x^{3} + 12 x^{2} + 48 x - 1

Solution

Saddle (- 4, - 65)

Solution steps

f^{'} (x) = 3 x^{2} + 24 x + 48

Find intervals:

Increasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

x^{3} + 12 x^{2} + 48 x - 1 : - 65

Saddle (- 4, - 65)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme y=x^3+12x^2+48x-1 ?
The extreme y=x^3+12x^2+48x-1 is Saddle(-4,-65)