What is the inverse of f(x)= 1/(x^2)+4 ?

The inverse of f(x)= 1/(x^2)+4 is sqrt(1/(x-4)),-sqrt(1/(x-4))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)= 1/(x^2)+4

inverse

f (x) = \frac{1}{x ^{2}} + 4

\frac{1}{x - 4}, - \frac{1}{x - 4}

Solution steps

y = \frac{1}{x ^{2}} + 4

Replace

x

with

y

x = \frac{1}{y ^{2}} + 4

Solve for

y, x = \frac{1}{y ^{2}} + 4

\frac{1}{x - 4}, - \frac{1}{x - 4}

What is the inverse of f(x)= 1/(x^2)+4 ?
The inverse of f(x)= 1/(x^2)+4 is sqrt(1/(x-4)),-sqrt(1/(x-4))