What is the inverse of y=(2x)/(x^2+49) ?

The inverse of y=(2x)/(x^2+49) is (1+sqrt(-49x^2+1))/x ,(1-sqrt(-49x^2+1))/x

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inverse of y=(2x)/(x^2+49)

inverse

y = \frac{2 x}{x ^{2} + 49}

\frac{1 + - 49 x ^{2} + 1}{x}, \frac{1 - - 49 x ^{2} + 1}{x}

Solution steps

y = \frac{2 x}{x ^{2} + 49}

Replace

x

with

y

x = \frac{2 y}{y ^{2} + 49}

Solve for

y, x = \frac{2 y}{y ^{2} + 49}

\frac{1 + - 49 x ^{2} + 1}{x}, \frac{1 - - 49 x ^{2} + 1}{x}

What is the inverse of y=(2x)/(x^2+49) ?
The inverse of y=(2x)/(x^2+49) is (1+sqrt(-49x^2+1))/x ,(1-sqrt(-49x^2+1))/x