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Popular Functions >

range of f(x)=-6x^2+10x-7

Solution

range

f (x) = - 6 x^{2} + 10 x - 7

Solution

f (x) \leq - \frac{17}{6}

+1

Interval Notation

(- \infty, - \frac{17}{6}]

Solution steps

Vertex of

- 6 x^{2} + 10 x - 7 :

Maximum

(\frac{5}{6}, - \frac{17}{6})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 6,

Vertex

(x_{v}, y_{v}) = (\frac{5}{6}, - \frac{17}{6})

f (x) \leq - \frac{17}{6}

Graph

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Frequently Asked Questions (FAQ)

What is the range of f(x)=-6x^2+10x-7 ?
The range of f(x)=-6x^2+10x-7 is f(x)<=-17/6