What is the extreme f(x)=4x^3-12x ?

The extreme f(x)=4x^3-12x is Maximum(-1,8),Minimum(1,-8)

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extreme f(x)=4x^3-12x

extreme points

f (x) = 4 x^{3} - 12 x

Maximum (- 1, 8), Minimum (1, - 8)

Solution steps

f^{'} (x) = 12 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

4 x^{3} - 12 x : 8

Maximum (- 1, 8)

Plug

x = 1

into

4 x^{3} - 12 x : - 8

Minimum (1, - 8)

Maximum (- 1, 8), Minimum (1, - 8)

What is the extreme f(x)=4x^3-12x ?
The extreme f(x)=4x^3-12x is Maximum(-1,8),Minimum(1,-8)