What is the domain of 1/(\sqrt[4]{x^2-7x)} ?

The domain of 1/(\sqrt[4]{x^2-7x)} is x 7

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domain of 1/(\sqrt[4]{x^2-7x)}

domain

x < 0 or x > 7

Interval Notation

(- \infty, 0) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 7

Find undefined (singularity) points:

x = 7, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 7

What is the domain of 1/(\sqrt[4]{x^2-7x)} ?
The domain of 1/(\sqrt[4]{x^2-7x)} is x<0\lor x>7